A
ALEX_AK
Member
Hello,
Is it correct if I just find
P(X>=25)=(50C25)*0.4^24*0.6*25
= 0.0405
This is also the size of the test. Am I right? Isn't it faster doing it this way? Why must we use the Normal Approx as in the solution?
Is it correct if I just find
P(X>=25)=(50C25)*0.4^24*0.6*25
= 0.0405
This is also the size of the test. Am I right? Isn't it faster doing it this way? Why must we use the Normal Approx as in the solution?