An Insurance company distinguishes between 3 types of fraudulent claims: Type 1: Legitimate claims hat are slightly exaggerated Type:2 Legitimate claim that are strongly exaggerated Type 3 :false claims Every fraudulent claim is characterised as exactly one of the three types. Assume that the probability of a newly submitted claim being a fraudulent claim of type 1 is 0.1. For type 2 this probability is 0.02, and for type 3 it is 0.003. The insurer uses a statistical software package to identify suspicious claims. If a claim is fraudulent of type 1, it is identified as suspicious by the software with probability 0.5. For a type 2 claim this probability is 0.7, and for type 3 it is 0.9. Of all newly submitted claims, 20% are identified by the software as suspicious. (ii) Calculate the probability that a claim that has been identified by the software as suspicious is: (a) a fraudulent claim of type 1, (b) a fraudulent claim of any type. (iii) Calculate the probability that a claim which has NOT been identified as suspicious by the software is infact fraudulent ? please provide solution other than mention in exam papers
dear sir let event A1, A2, and A3 denotes event of Type-1 , Type2, Type -3 and P(A1)=.1, P(A2)=.2 and P(A3)=.003 And P(S/A1)= .5 , P(S/A2)= .7 ,P(S/A3)= .9, therefore for question number 7 (ii) of a we have P(A1/S)={ P(S/A1)*P(A1)}/p(S) ={.5*.1}/.2=.25 for part (b) I am unable to structure the data , I know that we have to use "or" between P(A1/S)or P(A2/S) or P(A3/S) after this I am confused ???
This is correct. Yes - if you calculate P(A2|S) and P(A3|S) then the required probability is: P(A1|S) + P(A2|S) + P(A3|S) As they are mutually exclusive events so we add the "or" probabilities.
Dear Sir - Part -III- not clear to me ?? please clarify Question (iii) is some what tricky not understood?