Yes - use the ASET or revision notes from ActEd with clearer solutions
This question is slightly different to the standard compound distribution questions because we actually have a mixture distribution.
For the number of claims we have:
N | lambda = Poi(lambda)
where
lambda ~ gamma (2, 10)
So we need to use the formula at the top of page 16 of the Tables to get the mean and variance of N so we can then use that to get the mean and variance of S using the compound distribution formulae also on page 16 of the Tables.
So here we go:
E(N) = E[E(N|lambda)] = E[lambda] = 2/10 = 0.2
var(N) = E[var(N|lambda)] + var[E(N|lambda)]
= E[lambda] + var[lambda]
= 2/10 + 2/10² = 0.22
So now we can use:
E(S) = E(N)E(X) and var(S) = E(N)var(X) + E²(X)var(N)
Last edited: Mar 27, 2008