April 02 Qu 7) i)

Discussion in 'CT6' started by Brickie_Burns, Mar 14, 2008.

  1. Brickie_Burns

    Brickie_Burns Member

    I'm having difficulty following the examiners report for this question.

    We need to calculate the variance of a compound distribution, and I'm comfortable with the following:

    VAR = E[VAR[S|N]] + VAR[E[S|N]]

    = E[N]VAR[X] + VAR[N](E[X])^2

    However, in the examiners report, they go from the same starting position, and end up with:

    E[N]E[X^2] + VAR[N](E[X])^2

    The N here is actually lamda and is a poisson parameter, so I suspect this has something to do with it, but it's difficult to follow in the examiners report.

    Any tips?
     
  2. John Lee

    John Lee ActEd Tutor Staff Member



    Yes - use the ASET or revision notes from ActEd with clearer solutions :D

    This question is slightly different to the standard compound distribution questions because we actually have a mixture distribution.

    For the number of claims we have:

    N | lambda = Poi(lambda)

    where

    lambda ~ gamma (2, 10)

    So we need to use the formula at the top of page 16 of the Tables to get the mean and variance of N so we can then use that to get the mean and variance of S using the compound distribution formulae also on page 16 of the Tables.

    So here we go:

    E(N) = E[E(N|lambda)] = E[lambda] = 2/10 = 0.2

    var(N) = E[var(N|lambda)] + var[E(N|lambda)]
    = E[lambda] + var[lambda]
    = 2/10 + 2/10² = 0.22

    So now we can use:

    E(S) = E(N)E(X) and var(S) = E(N)var(X) + E²(X)var(N)
     
    Last edited: Mar 27, 2008
  3. Brickie_Burns

    Brickie_Burns Member

    Thanks for taking the time to look at that for me John, it's a big help.

    I have got ASET for CT6.....but only goes back as far as 2004?
     
  4. John Lee

    John Lee ActEd Tutor Staff Member

    Hmmm, good point. One of my students contacted admin and asked if it was possible to purchase the older CT6 ASET and she got it - so it must be possible. Do give them a ring on 01235 550005 or email acted@bpp.com if you want to get an older version.
     
  5. Catrina

    Catrina Member

    I confirm, I was able to purchase ASET April 2002 - Sep 2004 for £30. It arrived 2 days after I ordered it. In case you've already received it: In the ASET the question you're talking about is actually Q6 not Q7.
     
    Last edited by a moderator: Apr 3, 2008
  6. RaViShankar

    RaViShankar Member

    John, aren't we dealing with a new random variable S = 100∑Xi. So that Var(S) = 100^2( E(N)var(X) + E²(X)var(N))??

    Thanks!
     
  7. John Lee

    John Lee ActEd Tutor Staff Member

    At the very end we do add up 100 of these policies - but be careful with your variance:

    var(nX) = n²var(X)

    but

    var(X1 + ...+ Xn) = nvar(X)

    so it will actually be:

    var(S) = 100 × ....
     

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