A10_q7 ASET

Discussion in 'SP6' started by Edwin, Apr 9, 2013.

  1. Edwin

    Edwin Member

    We are asked to show that the price of the call is 20.60, it was frustrating to get a different answer several times this was because the ER and ASET seems to say that N(-0.4756) = 0.31718. My formula book says N(-0.4756) = 1 - N(0.48) = 1 - 0.68793 = 0.31207. Where am I going wrong?

    Only excel gives N(-0.4756) = 0.31718, how were we supposed to do this?
     
  2. morrisja

    morrisja Member

    Interpolate would be my guess.. Linear interpolation gets the correct answer.

    (0.44)*N(0.47)+(0.56)*N(0.48) = 0.6828192

    1-0.6828192 = 0.3171808


    Possibly some other interpolation is appropriate (I don't know what's in ST6), but that would be how I would get the probability if asked with no context.
     
  3. Edwin

    Edwin Member

    Thanx man....but normally the tables are applied without any need to interpolate, that's why I hadn't done it. Next time I struggle it' the first thing I try.
     

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