I know f(x) of U(-theta,theta) is (1/2*theta) ,but I have no idea about why P[X_1<=z]=(z+theta)/(2*theta). Is it scope of exam of CS1?If not, pleaze let me know.
It's just using the CDF of the uniform distribution given on page 13 of the Tables. Alternatively, you could just integrate between the start (-theta) and z to get this probability.