George Philip
Active Member
In part (iii) of this question, we are asked to solve 3px(1,2) in the 2 state (1,2) model
What we have found is that:
mu(1,2) = 0.2
mu(2,1) = 0.8
Using this, I have calculated P(1,1) = exp(-0.2) &
P(1,2) = 1 - P(1,1) = 1 - exp(-0.2)
P(2,2) = exp(-0.8) &
P(2,1) = 1 - P(2,2) = 1 - exp(-0.8)
The probability matrix will be of the form:
P =
0.8187 0.1813
0.55 0.45
therefore won't 3px(1,2) = P^3[1,2] = 0.242827 ?
But it doesn't match with the answer given.
Could someone please explain what I am doing wrong?
Thanks
What we have found is that:
mu(1,2) = 0.2
mu(2,1) = 0.8
Using this, I have calculated P(1,1) = exp(-0.2) &
P(1,2) = 1 - P(1,1) = 1 - exp(-0.2)
P(2,2) = exp(-0.8) &
P(2,1) = 1 - P(2,2) = 1 - exp(-0.8)
The probability matrix will be of the form:
P =
0.8187 0.1813
0.55 0.45
therefore won't 3px(1,2) = P^3[1,2] = 0.242827 ?
But it doesn't match with the answer given.
Could someone please explain what I am doing wrong?
Thanks