1. 

   Srijana Raghunath Member

   
   i) Using Derive the expression for v(t) , the present value of 1 due at time t
   
   Solution given is:
   
   
   Shouldn't it be:
   
   V(t) = exp(-0.08t), exp(-0.14t+0.3), exp(-0.44t-0.02t^2+5.3)

    

   Srijana Raghunath, Sep 9, 2017

   #1
2. 

   John Lee ActEd Tutor Staff Member

   Their answer is correct. If you show your working I can find the problem.

    

   John Lee, Sep 21, 2017

   #2

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