D
DanielZ
Member
Hi
On page 23 of the GLM chapter, the deviance of observation i is defined as
\( d(Y_i;\mu_i) = 2\omega_i \int_{\mu_i}^{Y_i} \frac{(Y_i -\zeta )}{V (\zeta )} d\zeta \)
where \(Y_i \) is the observed value, \(\mu_i \) is the fitted value and \(\omega_i \) is the weight.
Why do we need the integral in this expression? Also, why do we need the number 2?
thanks
On page 23 of the GLM chapter, the deviance of observation i is defined as
\( d(Y_i;\mu_i) = 2\omega_i \int_{\mu_i}^{Y_i} \frac{(Y_i -\zeta )}{V (\zeta )} d\zeta \)
where \(Y_i \) is the observed value, \(\mu_i \) is the fitted value and \(\omega_i \) is the weight.
Why do we need the integral in this expression? Also, why do we need the number 2?
thanks