G
gdmiccc
Member
Hi,
In the Dimensions section of Chapter 5, one of the examples states that since "exp(x) is dimensionless, we know that lambda(t) must be dimensionless, in other words t has the same dimension as 1/lambda"
Also, in the solution explanation of Question 5.7 is states that "Since the argument of exp(x) is dimensionless, we know that x has the same dimension as 1/lambda"
If anyone could elaborate or explain how "we know" these statements, I would greatly appreciate it. Thanks.
In the Dimensions section of Chapter 5, one of the examples states that since "exp(x) is dimensionless, we know that lambda(t) must be dimensionless, in other words t has the same dimension as 1/lambda"
Also, in the solution explanation of Question 5.7 is states that "Since the argument of exp(x) is dimensionless, we know that x has the same dimension as 1/lambda"
If anyone could elaborate or explain how "we know" these statements, I would greatly appreciate it. Thanks.