Hi - I was hoping for some help.
First to clarify, my understanding is that the question is asking us.. " what are a and b, such that the net profit of this portfolio is the same as just having the 5,000,000 call options with strike price of 100 - whilst taking tax into consideration ".
The first part I think I understand.
When 100 < St < 120, are -b call options are equal to 0 as we have max(St-120, 0) = 0. Therefore
0.6 * a * (St-100) = 0.6 * 5,000,000 * (St - 100)
Equating the coefficients, I understand a = 5,000,000.
The next part is where I am struggling to understand.
I suspect the 600,000 is coming from... " suppose the share price is 120 (the minimum of this band). From the original call options we now have 5,000,000 * 0.6 * (120 - 100) = 60,000,000 p = £ 600,000 .
I can't wrap my head around what the 0.2 * 5,000,000 * (S - 120) is doing.
It is confusing me that we have a call option with a strike of 120 and that side of the equation, because my understanding was it should only be relating to the 5,000,000 calls with strike of 100.
I see that this must be something to do with allowing for " the profit is now greater than 1,000,000 so you are being taxed at 80% ".
Through an example, I think I can see how this works
Suppose St = 140.
The original call would be the following...
(140 - 100) * 5,000,000 = 200,000,000 p = £2,000,000.
Now thinking about net profit after tax..
1,000,000 * 0.6 + 1,000,000 * 0.2 = £800,000 net profit.
Thinking about what the solution gives us..
converting to £ because 600,000 is in £
600,000 + 0.2 * 5,000,000 * (1.4 - 1.2) = 800,000.
So I think my is question is am 1) I along the right lines, and 2) how could I think about this in the exam / what is the interpreting of this side of the equation: 600,000 + 0.2 × 5,000,000(S − 120)
First to clarify, my understanding is that the question is asking us.. " what are a and b, such that the net profit of this portfolio is the same as just having the 5,000,000 call options with strike price of 100 - whilst taking tax into consideration ".
The first part I think I understand.
When 100 < St < 120, are -b call options are equal to 0 as we have max(St-120, 0) = 0. Therefore
0.6 * a * (St-100) = 0.6 * 5,000,000 * (St - 100)
Equating the coefficients, I understand a = 5,000,000.
The next part is where I am struggling to understand.
I suspect the 600,000 is coming from... " suppose the share price is 120 (the minimum of this band). From the original call options we now have 5,000,000 * 0.6 * (120 - 100) = 60,000,000 p = £ 600,000 .
I can't wrap my head around what the 0.2 * 5,000,000 * (S - 120) is doing.
It is confusing me that we have a call option with a strike of 120 and that side of the equation, because my understanding was it should only be relating to the 5,000,000 calls with strike of 100.
I see that this must be something to do with allowing for " the profit is now greater than 1,000,000 so you are being taxed at 80% ".
Through an example, I think I can see how this works
Suppose St = 140.
The original call would be the following...
(140 - 100) * 5,000,000 = 200,000,000 p = £2,000,000.
Now thinking about net profit after tax..
1,000,000 * 0.6 + 1,000,000 * 0.2 = £800,000 net profit.
Thinking about what the solution gives us..
converting to £ because 600,000 is in £
600,000 + 0.2 * 5,000,000 * (1.4 - 1.2) = 800,000.
So I think my is question is am 1) I along the right lines, and 2) how could I think about this in the exam / what is the interpreting of this side of the equation: 600,000 + 0.2 × 5,000,000(S − 120)