Hello Page 4 of the Tables gives the general solution to a difference equation of this form. As we have: \( \rho _k = 12/35 * \rho_{k-1} - 1/35 * \rho _{k-2} \) We first need to solve the quadratic equation: \( 1 * \lambda ^ 2 - 12/35 * \lambda + 1/35 = 0 \) This gives roots of \( 1/5 \) and \( 1/7 \). So, the general solution is: \( A * (1/5) ^ k + B * (1/7)^k \) Hope this helps. Andy
