• We are pleased to announce that the winner of our Feedback Prize Draw for the Winter 2024-25 session and winning £150 of gift vouchers is Zhao Liang Tay. Congratulations to Zhao Liang. If you fancy winning £150 worth of gift vouchers (from a major UK store) for the Summer 2025 exam sitting for just a few minutes of your time throughout the session, please see our website at https://www.acted.co.uk/further-info.html?pat=feedback#feedback-prize for more information on how you can make sure your name is included in the draw at the end of the session.
  • Please be advised that the SP1, SP5 and SP7 X1 deadline is the 14th July and not the 17th June as first stated. Please accept out apologies for any confusion caused.

Q&A Bank 1.30(ii)

D

DMF

Member
Hello,

I am working through the solution to Q1.30(ii). Using the solution in part (i) the integral of [x . f(x)] between 100 and infinity is calculated. If x = infinity then am I right in thinking that the area under a normal distribution curve will = 1. Hence the 1 in the solution?

Thanks!
 

Attachments

  • WIN_20180722_13_57_30_Pro.jpg
    WIN_20180722_13_57_30_Pro.jpg
    467.2 KB · Views: 9
Hi DMF,

As it happens, I'm working on the same question today. Yes, I think your understanding is correct but it would be good to hear this from one of the tutors/someone who has given it more thought.

Related to this, I'd be grateful if someone could please confirm why the sigma^2 term disappears from the limits whenever a fixed value of X is used in the calculation (e.g. x = 100)? Is this because the value of 100 is a constant and so has no variance? See first couple of lines of calculations top of page 41 for example of sigma^2 being excluded from some of the calcs.

Many thanks!
 
Yes, since \(ln \infty \rightarrow \infty \) (albeit very slowly) and \(\Phi(\infty)=1\).

The \(\sigma ^2\) is not included in the terms for the second integral because \(k=0\).
 
Thanks John, this helpful. I was getting distracted by the fact that it started at 100.
 
Back
Top