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September 2007 11 (iv)

J

Janboyd

Member
Please could someone explain how we reach 8 degrees of freedom?
 
In core reading Page 39 chap 3 , we have no of degree of freedom formula as (r-2q+s).
Where r denotes no of triplets,q denotes no of pairs and s denotes no of states.
Now in this question r = 12 as observed,s= 3 but q= 6 and not 3.So df will be calculated as (12-6*2+3)=3
the critical value of chi square 3 at 5% is 7.815.
PS : I don't think it should be 8 as given in the solution.
 
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