Generator(u) = 1/a ((u^-a)-1), where a is alpha. Alpha >= -1. It was mentioned that the Clayton generator is strict only when a > 0. May I know why is Clayton generator strict only when a > 0? For a generator to be strict, it should fulfil, Generator(0) = infinity If I have a=2 and u=0, Generator(0) = 1/2 ((0^-2)-1) = -1/2 This is not inifinity. Not sure on how is the condition of a > 0 being derived?
