Has the expected value of Tx been covered in CT5?

I ask this because I'm solving question 1.2 of the Q&A Bank part 1, CT 5, and in part (v),
E(Tx) = ex, value of e is taken from AM 92 , page 84. (Sorry for the lack of appropriate edits)

Can anyone please confirm?

 

No, not covered in CT5, but is one of the few things that are assumed knowledge from CT4.
Basically, E[Kx] = ex (with no little circle above it), and it is these that are shown on page 82/83 of the AM92 Tables.
E[Tx] = ex WITH a little circle above the "e". These are the ones that are tabulated for ELT15 for example on pages 68 and 69.
ex (no circle) is approximately equal to e (with circle) - 0.5.
To get the formulae, ex is the same as ax (in arrears) at 0% interest, and ex (with circle) is the same as a-bar x (continuous life annuity) at 0% interest. So you can look at the formulae for these annuities and just make v=1 throughout.
That's really all you need to know
Robert

 

Thank you Robert. Very helpful.

 

thanks