IAI May 2012

[kartik_newpro]

This was in yesterday's CT3 paper. I do not remember the wordings of th questions properly. But I guess this is what they were asking.

e_i, i = 1,2,3,.... are normally distributed with mean 0 and variance 1.

alpha is an unknown parameter. The following two equations were given -

y_1 = alpha + e_i
y_2 = 3*alpha + e_i

What is the regression model?

 

[bpatra]

I am surprised no one has replied.Now that the question paper is available in IAI website somebody should come forward. I request Mr Jhon Lee to look at the question.

 

[John Lee]

I am surprised no one has replied.Now that the question paper is available in IAI website somebody should come forward. I request Mr Jhon Lee to look at the question.

To be honest it is not clear to me.

Since α is a parameter then perhaps the value infront is the x value? In which case it would be yi = αxi + ei.

 

[kartik_newpro]

To be honest it is not clear to me.

Since α is a parameter then perhaps the value infront is the x value? In which case it would be yi = αxi + ei.

John, I would request you to look at this question from the IAI website and tell us what you think the solution should be. I still havent gotten anywhere with this question.

Thanks.

 

[John Lee]

John, I would request you to look at this question from the IAI website and tell us what you think the solution should be. I still havent gotten anywhere with this question.

I'm a bit confused. I did look and the above was my suggested answer.

 

[manish.rex]

This was in yesterday's CT3 paper. I do not remember the wordings of th questions properly. But I guess this is what they were asking.

e_i, i = 1,2,3,.... are normally distributed with mean 0 and variance 1.

alpha is an unknown parameter. The following two equations were given -

y_1 = alpha + e_i
y_2 = 3*alpha + e_i

What is the regression model?

Regression model is : Yi = alpha*Xi + ei

solve : Sum((ei)^2) = (.6 - *alpha)^2 + (1.8 - 3*alpha)^2
by least squares method.